Let the first number be x

The second will be (x+1)

Their sum is = 115

So,

x+(x+1)=115

2x+1=115

2x=115-1

2x=114

x=114/2

x=57

x=57, (x+1)=58

57 and 58 are two consecutive numbers whose sum is 115.

Let the first number be x

The second will be (x+1)

Their sum is = 115

So,

x+(x+1)=115

2x+1=115

2x=115-1

2x=114

x=114/2

x=57

x=57, (x+1)=58

57 and 58 are two consecutive numbers whose sum is 115.

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