How to Find Three Consecutive Even Integers Whose Sum is 180? | TIRLA ACADEMY

Let the first even integer be x

The second will be (x+2)

Third even integer = (x+4)

Their sum is = 180

So,

x+(x+2)+(x+4)=180

3x+6=180

3x=180-6

3x=174

x=174/3

x=58

x=58, (x+2)=60, (x+4)=62

58, 60, and 62 are three consecutive even integers whose sum is 180.