Let the first integer be x
The second will be (x+1)
Third integer = (x+2)
Fourth = (x+3)
Their sum is = 54
So,
x+(x+1)+(x+2)+(x+3)=54
4x+6=54
4x=54-6
4x=48
x=48/4
x=12
x=12, (x+1)=13, (x+2)=14, (x+3)=15
12, 13, 14, and 15 are four consecutive integers whose sum is 54.