Let the first integer be x

The second will be (x+1)

Third integer = (x+2)

Fourth = (x+3)

Their sum is = 54

So,

x+(x+1)+(x+2)+(x+3)=54

4x+6=54

4x=54-6

4x=48

x=48/4

x=12

x=12, (x+1)=13, (x+2)=14, (x+3)=15

12, 13, 14, and 15 are four consecutive integers whose sum is 54.